Skip to content
Engineering reference // Fluid mechanics // Part 1

Drawing No. EH–FM–007 // Fluid Mechanics & Piping

Fluid Mechanics Formula Sheet

Part 1 of the EngineerHub fluid-mechanics reference series: internal flow and pump systems. It connects flow rate, velocity, pressure, friction, pump head and cavitation. Each section includes variable definitions, SI and US customary units, a worked example and a direct link to the corresponding EngineerHub calculator.

From continuity to NPSH

Use the sheet as a quick reference or follow it in sequence. The equations assume conventional engineering sign conventions; always use a consistent unit system inside a calculation.

Reference conventions

g = 9.80665 m/s²Standard gravitational acceleration; ≈ 32.174 ft/s²
γ = ρgSpecific weight: N/m³ in SI, lbf/ft³ in US customary
SG = ρ/ρrefSpecific gravity: density ratio to the stated reference liquid, commonly water
ν = μ/ρKinematic viscosity: m²/s or ft²/s

Energy grade line along a pipe run

ENERGY AND HYDRAULIC GRADE LINES reservoir P pump, Hp datum EGL HGL v²/2g friction slope hƒ = f(L/D)v²/2g The EGL always falls in the flow direction except across a pump; the gap to the HGL is velocity head.

01 // Continuity

Conservation of mass links flow area and velocity. For an incompressible fluid of constant density, volumetric flow rate is conserved through a single streamtube.

Incompressible steady flow
Q = A v    →    A₁v₁ = A₂v₂
ṁ = ρQ = ρAv
SymbolMeaningSI unitsUS customary
QVolumetric flow ratem³/s, L/sft³/s, gpm
AFlow area normal to velocityft², in²
vMean cross-sectional velocitym/sft/s
Mass flow ratekg/slbm/s
ρFluid densitykg/m³lbm/ft³

For compressible flow, conserve mass rather than volume: ρ₁A₁v₁ = ρ₂A₂v₂. For a circular pipe, A = πD²/4. For non-circular internal flow, use hydraulic diameter Dh = 4A/Pw, where Pw is wetted perimeter.

Worked example — flow from pipe diameter and velocity

Given: water flows through a 100 mm internal-diameter pipe at an average velocity of 2.0 m/s.

A = π(0.100 m)² / 4 = 0.007854 m²
Q = Av = 0.007854 × 2.0 = 0.01571 m³/s
Answer: Q ≈ 0.0157 m³/s = 15.7 L/s.

US check: US equivalent: Q ≈ 249 US gpm.

Area–velocity relationship

A₁ large → v₁ lower A₂ smaller → v₂ higher For incompressible steady flow: A₁v₁ = A₂v₂
Continuity does not create energy; it only enforces mass conservation. Pressure changes require Bernoulli / momentum relations.

02 // Bernoulli equation

Bernoulli expresses mechanical energy per unit weight along a streamline. The extended form includes pump head, turbine extraction and irreversible head losses.

Ideal mechanical-energy form
p/γ + αv²/(2g) + z = H
Extended engineering form
p₁/γ + α₁v₁²/(2g) + z₁ + Hₚ = p₂/γ + α₂v₂²/(2g) + z₂ + Hₜ + hL
SymbolMeaningSI unitsUS customary
pStatic pressurePa, kPapsf or psi (convert psi × 144 before p/γ)
γSpecific weight = ρgN/m³lbf/ft³
ρMass densitykg/m³lbm/ft³
αKinetic-energy correction coefficientdimensionlessdimensionless
vMean fluid velocitym/sft/s
zElevation datummft
HₚHead added by pumpm fluidft fluid
HₜHead removed by turbinem fluidft fluid
hLTotal irreversible head lossm fluidft fluid

The ideal form assumes steady, incompressible flow along a streamline. For ordinary turbulent pipe-flow screening, α ≈ 1 is commonly used; for fully developed laminar circular-pipe flow, α = 2. The extended form adds shaft work and irreversible head loss.

Worked example — reservoir to atmospheric discharge

Given: water is pumped from a large open reservoir to an atmospheric pipe discharge 10 m higher. The discharge velocity is 2.0 m/s, total head loss is 3.0 m, and the source-reservoir free-surface velocity is negligible.

Hₚ = Δz + v₂²/(2g) + hL
Hₚ = 10 + 2²/(2×9.80665) + 3 = 13.204 m
Answer: required pump head ≈ 13.2 m under the stated assumptions.

US check: US equivalent: required pump head ≈ 43.32 ft.

Head terms are all lengths

Bernoulli is especially convenient because pressure head, velocity head and elevation head are expressed in the same unit: metres or feet of the flowing fluid. Using specific weight γ keeps the head equation dimensionally clean in both SI and US customary systems.

Pressure head p/γ
Velocity head αv²/2g
Elevation z
hₚ = Δp/γ    ;    Δp = γh

US: h(ft) = 144·Δp(psi)/γ(lbf/ft³). For water-like liquids, h(ft) ≈ 2.31·Δp(psi)/SG.

Common mistake: do not insert psi directly into p/γ unless the 144 in²/ft² conversion is included. Gauge pressures may cancel in open-reservoir balances, but NPSH calculations require absolute pressure.

03 // Reynolds number

Reynolds number compares inertial and viscous effects and is the primary regime indicator for internal flow.

Internal pipe flow
Re = ρvD/μ = vD/ν
SymbolMeaningSI unitsUS customary
ReReynolds numberdimensionlessdimensionless
ρDensitykg/m³lbm/ft³
vMean velocitym/sft/s
DPipe internal diameter / hydraulic diametermft
μDynamic viscosityPa·slbm/(ft·s)
νKinematic viscosity = μ/ρm²/sft²/s

For circular pipe flow, a common engineering classification is laminar Re ≲ 2300, transition ≈ 2300–4000, and turbulent Re ≳ 4000. For non-circular ducts use Dh = 4A/Pw. Transition depends on inlet disturbances, roughness and geometry.

Worked example — water in a 50 mm pipe

Given: 20°C water, ρ = 998 kg/m³, μ = 1.002×10⁻³ Pa·s, v = 2.0 m/s, D = 0.050 m.

Re = (998×2.0×0.050)/(1.002×10⁻³) ≈ 9.96×10⁴
Answer: Re ≈ 99,600, clearly in the turbulent regime for ordinary internal pipe flow.

US check: Using ρ ≈ 62.30 lbm/ft³, μ ≈ 6.733×10⁻⁴ lbm/(ft·s), v ≈ 6.562 ft/s and D ≈ 0.1640 ft gives the same Re ≈ 99,600.

Why Reynolds matters downstream

  • It determines whether laminar friction factor f = 64/Re applies.
  • It affects turbulent friction-factor correlations such as Colebrook or Swamee–Jain.
  • It influences heat-transfer and mass-transfer correlations.
  • It helps interpret whether a scale model is dynamically similar.
Open Moody Chart

04 // Darcy–Weisbach major loss

The Darcy–Weisbach equation gives frictional loss along a straight pipe. It is dimensionally consistent and widely applicable when the Darcy friction factor is known.

Head loss
hƒ = f (L/D) · v²/(2g)
Δpƒ = γhƒ
SymbolMeaningSI unitsUS customary
Major head lossm fluidft fluid
ΔpƒMajor pressure lossPapsf; divide by 144 for psi
fDarcy friction factordimensionlessdimensionless
LStraight pipe lengthmft
DInternal / hydraulic diametermft
vMean velocitym/sft/s
gGravitational accelerationm/s²ft/s²
γSpecific weightN/m³lbf/ft³

Important: this page uses the Darcy friction factor. The Fanning factor is one quarter of the Darcy value: fF = fD/4.

Worked example — straight-pipe loss

Given: f = 0.020, L = 50 m, D = 0.100 m, v = 2.0 m/s, water density ≈ 998 kg/m³.

hƒ = 0.020 × (50/0.100) × 2²/(2×9.80665) = 2.039 m
Δpƒ = γhƒ = ρghƒ ≈ 998×9.80665×2.039 ≈ 19.96 kPa
Answer: major loss ≈ 2.04 m of water, or about 20.0 kPa.

US check: US equivalent: hƒ ≈ 6.691 ft and Δpƒ ≈ 2.895 psi.

Choosing the Darcy friction factor

Laminar circular pipe:

f = 64/Re

Turbulent pipe — Colebrook–White:

1/√f = −2 log₁₀[(ε/D)/3.7 + 2.51/(Re√f)]

Here ε is absolute roughness and ε/D is relative roughness. Colebrook is implicit in f; a Moody chart or validated explicit approximation is often more convenient.

Transition region: friction is less predictable; do not treat Re = 2300 or 4000 as a perfectly sharp physical switch.

05 // Minor / local losses

Fittings, entrances, exits, valves and local geometry changes are commonly represented by dimensionless loss coefficients.

Local head loss
hₘ = ΣK · v²/(2g)
K = f · Leq/D    →    Leq = KD/f
SymbolMeaningSI unitsUS customary
hₘMinor / local head lossm fluidft fluid
KLoss coefficient for fitting / componentdimensionlessdimensionless
vReference velocity associated with Km/sft/s
LeqEquivalent straight-pipe lengthmft
fDarcy friction factordimensionlessdimensionless

Use the velocity specified for the coefficient source. For area changes, a coefficient may be based on upstream, downstream or throat velocity; mixing definitions can produce large errors.

Worked example — fittings represented by ΣK

Given: combined fitting coefficient ΣK = 4.5 and pipe velocity v = 2.0 m/s.

hₘ = 4.5 × 2²/(2×9.80665) = 0.918 m
Answer: local losses add approximately 0.918 m of head loss.

US check: US equivalent: local head loss ≈ 3.011 ft.

“Minor” does not mean negligible

In short piping systems, suction lines, valve stations or heavily fitted process systems, local losses can equal or exceed straight-pipe friction.

Do not double count: if a vendor or design source already incorporates a component pressure drop explicitly, do not also add an independent K value for the same loss.

06 // Pump hydraulic and shaft power

Pump head becomes hydraulic power through flow rate and fluid specific weight. Pump and motor efficiencies determine the shaft and electrical input required.

Hydraulic power
Pₕ = γQH = ρgQH
Ppump,input = Pₕ/ηₚ ; Pelec = Pₕ/(ηₚηₘ)
US customary practical form
Pₕ(hp) = Q(gpm)·H(ft)·SG / 3960
Ppump,input(hp) = Q·H·SG / (3960·ηₚ)
SymbolMeaningSI unitsUS customary
PₕHydraulic power delivered to fluidW, kWhp
γSpecific weightN/m³lbf/ft³
ρMass densitykg/m³lbm/ft³
QVolumetric flow ratem³/sft³/s, US gpm
HTotal pump headm fluidft fluid
ηₚPump efficiencyfraction or %fraction or %
ηₘMotor efficiencyfraction or %fraction or %
SGSpecific gravity for practical US pump-power formdimensionlessdimensionless

Use total dynamic head at the actual operating point, not only static elevation. Total head can include static head, pressure difference, velocity-head change and pipe/fitting losses. The 3960 constant is the conventional US gpm–ft–horsepower conversion used with specific gravity.

Worked example — shaft power

Given: water, ρ = 998 kg/m³, Q = 0.020 m³/s, pump head H = 25 m, pump efficiency ηₚ = 0.75.

Pₕ = 998×9.80665×0.020×25 = 4.894 kW
Pshaft = 4.894/0.75 = 6.525 kW
Answer: hydraulic power ≈ 4.89 kW; required shaft power ≈ 6.52 kW before any motor-efficiency allowance.

US check: US equivalent: hydraulic power ≈ 6.56 hp and pump shaft/input power ≈ 8.75 hp. The conventional 3960 form gives essentially the same result, subject to its rounded conversion constant.

Energy chain

Electrical input Pelec Shaft power Pshaft Fluid power γQH ηmotor and ηpump account for losses
Efficiency should be evaluated near the actual pump operating point rather than assumed constant across the full curve.

07 // Net positive suction head (NPSH)

NPSH measures how far the pump suction condition lies above the liquid vapor-pressure head. Use absolute pressures.

At pump suction reference
NPSHₐ = pₛ,abs/γ + vₛ²/(2g) − pᵥ/γ
Open suction reservoir — useful system form
NPSHₐ = pₐtm/γ + zstatic − hL,suction − pᵥ/γ
SymbolMeaningSI unitsUS customary
NPSHₐNet positive suction head availablem liquidft liquid
γLiquid specific weightN/m³lbf/ft³
pₛ,absAbsolute static suction pressurePa absolutepsia (×144 for psf in p/γ)
vₛSuction-pipe mean velocitym/sft/s
pᵥLiquid vapor pressure at temperaturePa absolutepsia
pₐtmAtmospheric pressurePa absolutepsia
zstaticLiquid-surface elevation above pump datum; negative for liftmft
hL,suctionSuction-line lossesm liquidft liquid

NPSH required is a pump characteristic supplied by the manufacturer for a defined test criterion. Published rotodynamic-pump curves commonly use NPSH3: the NPSH available at which total head has fallen by 3% at the specified condition. NPSHA equal to NPSH3 therefore does not mean zero cavitation or full non-cavitating performance. Establish margin from applicable pump/vendor/project guidance rather than assuming one universal margin.

US customary: convert pressure to head as h(ft) = 144·p(psia)/γ(lbf/ft³). Use absolute pressure for atmospheric, suction and vapor-pressure terms.

Worked example — open tank suction

Given: water at about 20°C, ρ = 998 kg/m³, atmospheric pressure 101.325 kPa absolute, vapor pressure 2.34 kPa absolute, liquid surface 2.0 m above the pump, and suction-line loss 1.0 m.

NPSHₐ = (pₐtm−pᵥ)/γ + zstatic − hL,suction
NPSHₐ = (101.325−2.34)×10³/(998×9.80665) + 2.0 − 1.0
NPSHₐ ≈ 11.11 m
Answer: NPSH available ≈ 11.1 m of water.

US check: US equivalent: NPSHA ≈ 36.46 ft of water.

This is not a complete cavitation guarantee. Compare the result with the pump manufacturer's NPSHr at the actual flow and apply the project/vendor margin criteria.

What lowers NPSHa?

  • Higher liquid temperature → higher vapor pressure.
  • Higher elevation above sea level → lower atmospheric pressure.
  • Longer / smaller suction piping → greater suction friction loss.
  • Higher flow → greater velocity and usually greater suction losses.
  • Liquid level below the pump centerline → negative static contribution.

08 // How the equations fit together

A pipe-and-pump calculation usually moves through these relationships in sequence rather than treating them as isolated equations.

GeometryArea and diameter
ContinuityQ ↔ velocity
ReynoldsIdentify regime
FrictionMajor + local losses
BernoulliTotal system head
Pump powerγQH / efficiency
NPSHCheck suction margin
System head
Hsystem = Hstatic + Hpressure + hL,major + hL,minor
For many turbulent systems: Hsystem ≈ Hstatic + KQ²

The pump operating point is the intersection of the pump curve and the system curve. Friction-factor variation means the exact system curve is not always a perfect Q² parabola.

Iteration is normal. Pipe diameter changes velocity, Reynolds number, friction factor, head loss, pump duty and NPSH. A realistic design often requires several passes or a coupled system-curve calculation.

09 // Quick formula summary

Use this table as the compact print reference. The detailed sections above contain definitions and assumptions.

TopicEquationMain purposeEngineerHub tool
ContinuityQ = AvRelate area, velocity and volumetric flowPipe Velocity
Hydraulic diameterDh = 4A/PwCharacteristic diameter for non-circular internal flowReynolds Number
Bernoullip/γ + αv²/2g + z = HMechanical energy / head balanceBernoulli
ReynoldsRe = ρvD/μClassify internal-flow regimeReynolds Number
Friction factorf = 64/Re (laminar); Colebrook for turbulentDetermine Darcy friction factorMoody Chart
Major losshƒ = f(L/D)v²/(2g)Straight-pipe friction lossDarcy–Weisbach
Minor losshₘ = ΣK v²/(2g)Fittings / valves / local geometryPipe Flow & Head Loss
Pressure ↔ headΔp = γhConvert pressure loss and head lossPipe Flow & Head Loss
Pump powerPₕ = γQH = ρgQHConvert hydraulic duty to powerPump System
NPSH availablepₛ,abs/γ + vₛ²/2g − pᵥ/γAssess suction condition above vapor pressurePump NPSH

10 // Assumptions, units & reference notes

The formulas are simple; choosing the correct inputs and conventions is the real engineering work.

11 // Related fluid mechanics tools

Use the formula sheet as the entry point, then move to the full calculators for input handling, unit conversion and expanded assumptions.