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Engineering reference // HVAC

Drawing No. EH–TH–024 // Thermal Engineering & HVAC

HVAC Formula Sheet

A practical HVAC reference connecting envelope transmission, airflow, psychrometrics, moisture control, ventilation, fan power and equipment efficiency. Mass-based moist-air equations are emphasized because air density and psychrometric properties vary with pressure, temperature and humidity.

Fast reference, with engineering context

Use the equations directly for screening calculations, then open the linked EngineerHub tools for input handling and unit conversion. Formula applicability and major limitations are stated beside each relation.

Reference conventions

q̇ = UAΔTEnvelope transmission
q̇ = ṁcₚΔTSensible air heat
q̇ = ṁdaΔhTotal moist-air heat
ACH = 3600Q/VAir changes per hour

Room sensible and latent heat balance

ROOM HEAT BALANCE CONDITIONED SPACE volume V, indoor Tin, Win ENVELOPE GAIN q̇ = UA(Tout − Tin) INFILTRATION ACH · V / 3600 INTERNAL GAINS people, lighting, equipment SUPPLY AIR q̇s = ṁda cp,ma ΔT q̇t = ṁda(h₂ − h₁) MOISTURE ṁw = ṁda(W₁ − W₂) Sensible load moves temperature; latent load moves humidity ratio. Both must balance.
HVAC sizing combines transmission, internal/solar loads, ventilation/infiltration and supply-air psychrometrics. A single formula rarely represents the full building load.

01 // Envelope transmission heat

For steady transmission through an assembly represented by an overall U-factor, heat flow is proportional to area and temperature difference.

Core relation
q̇ = UA(Tin − Tout)
R″ = 1/U
SymbolMeaningSI unitsUS customary
Transmission heat rateWBtu/h
UOverall assembly U-factorW/(m²·K)Btu/(h·ft²·°F)
AAssembly areaft²
ΔTIndoor-outdoor temperature differenceK°F
Worked example — winter wall transmission

Given: U = 0.35 W/(m²·K), A = 120 m², indoor-outdoor ΔT = 25 K.

q̇ = 0.35×120×25 = 1050 W
Answer: q̇ = 1.05 kW.

US check: ≈3583 Btu/h.

This is transmission only; infiltration, ventilation, thermal bridges and internal/solar gains are separate.

For dynamic cooling loads, thermal storage and solar/radiant effects matter. ASHRAE heat-balance or RTS methods are more complete than steady UAΔT.

02 // Sensible heat carried by air

For a known dry-air mass flow, the sensible heat associated with a dry-bulb temperature change is approximated with moist-air specific heat.

Core relation
s ≈ ṁda cp,ma ΔT
cp,ma ≈ 1.006 + 1.86W   kJ/(kgda·K)
SymbolMeaningSI unitsUS customary
ṁdaDry-air mass flowkgda/slbda/h
cp,maMoist-air heat capacity per kg dry airkJ/(kgda·K)Btu/(lbda·°F)
WHumidity ratiokgw/kgdalbw/lbda
ΔTDry-bulb temperature changeK°F
Worked example — cooling supply air sensibly

Given: ṁda = 1.5 kg/s, cp ≈ 1.006 kJ/(kg·K), ΔT = 12 K.

q̇s = 1.5×1.006×12 = 18.108 kW
Answer: q̇s ≈ 18.1 kW.

US check: ≈61,800 Btu/h.

For precision, use the actual moist-air state instead of a fixed volumetric ‘air factor’.

ASHRAE also publishes convenient standard-air volumetric factors, but mass-based calculation is more accurate when altitude or temperature differs significantly from standard conditions.

03 // Total moist-air heat

The total heating/cooling rate of an airstream follows directly from the moist-air enthalpy difference.

Core relation
t = ṁda(h₂ − h₁)
da = V̇ / v
SymbolMeaningSI unitsUS customary
hMoist-air enthalpykJ/kgdaBtu/lbda
ṁdaDry-air mass flowkgda/slbda/h
Moist-air volume flowm³/scfm
vSpecific volume per dry airm³/kgdaft³/lbda
q̇tTotal heat ratekWBtu/h
Worked example — cooling a moist-air stream

Given: ṁda = 1.5 kg/s; entering h₁ = 60 kJ/kgda; leaving h₂ = 42 kJ/kgda.

q̇removed = 1.5(60−42) = 27.0 kW
Answer: 27.0 kW of total cooling.

US check: ≈92,100 Btu/h.

Use a consistent psychrometric enthalpy reference within one unit system.

Cooling below dew point also removes condensate. A complete coil energy balance may include the enthalpy of drained condensate.

04 // Humidity ratio from vapor pressure

At a known total pressure, humidity ratio follows from water-vapor partial pressure.

Core relation
W = 0.621945 pw/(p − pw)
pw ≈ φ pws(Tdb)
SymbolMeaningSI unitsUS customary
WHumidity ratiokgw/kgdalbw/lbda
pwWater-vapor partial pressurePa or kPapsia
pTotal absolute pressurePa or kPapsia
φRelative humidityfraction or %fraction or %
pwsSaturation vapor pressure at dry bulbPa or kPapsia
Worked example — 25°C and 50% RH at sea-level pressure

Given: Tdb = 25°C, RH = 50%, pws ≈ 3.1692 kPa, p = 101.325 kPa.

pw = 0.5×3.1692 = 1.5846 kPa
W = 0.621945×1.5846/(101.325−1.5846) = 0.009881 kg/kg
Answer: W ≈ 9.88 g/kg dry air.

Use local station pressure for altitude-sensitive psychrometrics.

Relative humidity alone does not identify moisture content; the same RH at different temperatures corresponds to different humidity ratio and dew point.

05 // Cooling and dehumidification moisture removal

The water removed from an airstream follows directly from the humidity-ratio reduction.

Core relation
w = ṁda(W₁ − W₂)
latent,approx ≈ ṁw hfg
SymbolMeaningSI unitsUS customary
ṁwCondensate / moisture-removal ratekg/slb/h
ṁdaDry-air mass flowkg/slb/h
W₁,W₂Entering/leaving humidity ratiokg/kgdalb/lbda
hfgApprox. vaporization enthalpykJ/kgBtu/lb
Worked example — dehumidifying an airstream

Given: ṁda = 1.5 kg/s, W₁ = 0.012, W₂ = 0.008 kg/kgda.

ṁw = 1.5(0.012−0.008) = 0.006 kg/s
ṁw = 21.6 kg/h
Approx. latent rate using 2500 kJ/kg = 15 kW
Answer: 21.6 kg/h of condensate; approximate latent component 15 kW.

Use the full moist-air/condensate enthalpy balance for accurate coil duty.

The 2500 kJ/kg latent approximation is convenient but not a substitute for a psychrometric energy balance when coil leaving conditions and condensate temperature matter.

06 // Air changes per hour

ACH normalizes ventilation or infiltration flow to the room volume.

Core relation
ACH = 3600 V̇ / Vroom
V̇ = ACH·Vroom/3600
SymbolMeaningSI unitsUS customary
ACHAir changes per hourh⁻¹h⁻¹
Volumetric airflowm³/scfm
VroomRoom volumeft³
Worked example — ventilating a 250 m³ room

Given: V̇ = 0.25 m³/s and room volume = 250 m³.

ACH = 3600×0.25/250 = 3.6 h⁻¹
Answer: ACH = 3.6 air changes/h.

US check: 0.25 m³/s ≈ 530 cfm.

ACH is a volumetric turnover metric; it does not directly measure contaminant-removal effectiveness.

Outdoor-air requirements may be based on occupancy, floor area, contaminant generation or code-prescribed minimums rather than ACH alone.

07 // Fan / air-moving power

Ideal air power is pressure rise times volumetric flow; divide by fan/system efficiency for shaft or electrical input as appropriate.

Core relation
P = Δp V̇ / η
Pair = Δp V̇
SymbolMeaningSI unitsUS customary
PInput power represented by ηWhp
ΔpFan total/static pressure rise, consistently definedPain. w.g. or lbf/ft²
Airflowm³/scfm
ηFan/drive efficiency used in equationfractionfraction
Worked example — fan moving 2.5 m³/s

Given: V̇ = 2.5 m³/s, pressure rise = 600 Pa, overall efficiency = 0.65.

P = 600×2.5/0.65 = 2308 W
Answer: P ≈ 2.31 kW.

US check: ≈3.09 hp.

Be explicit whether η is fan-only, fan+drive, or wire-to-air efficiency.

Actual system operating point is set by the intersection of the fan curve and system-resistance curve. Filters and dampers change pressure demand.

08 // COP and EER

Coefficient of performance compares useful heating/cooling output to input power. EER is a common I-P cooling-efficiency expression.

Core relation
COP = Q̇useful/Pinput
EER [Btu/(Wh)] ≈ 3.41214 × COP
SymbolMeaningSI unitsUS customary
COPCoefficient of performancedimensionlessdimensionless
Q̇usefulHeating or cooling outputWBtu/h
PinputElectrical inputWW
EEREnergy efficiency ratioBtu/(Wh)
Worked example — heat pump at one operating point

Given: Useful heat output = 12 kW; electrical input = 3 kW.

COP = 12/3 = 4.0
EER-equivalent = 3.41214×4 = 13.65 Btu/(Wh)
Answer: COP = 4.0; equivalent EER ≈ 13.65.

Do not compare COP/EER values measured at different rating conditions as though they were identical.

Seasonal metrics (SEER, SCOP, HSPF and regional variants) include part-load and climate assumptions and are not simple point COPs.

09 // Quick formula summary

Compact print reference. Use the detailed sections above for definitions and limitations.

TopicEquationPurposeTool
Envelopeq̇=UAΔTTransmissionWall heat transfer
Sensible airq̇=ṁcₚΔTDry-bulb loadHVAC BTU
Total moist airq̇=ṁdaΔhSensible + latentHVAC BTU
Humidity ratioW=0.621945pw/(p−pw)Moisture stateWet bulb
Moisture removalṁw=ṁdaΔWCondensateDew point
ACHACH=3600Q/VVentilation turnoverVentilation
Fan powerP=ΔpQ/ηAir-moving powerVentilation
COPCOP=Qout/PinEquipment efficiencyHeat pump

10 // Assumptions & limitations

Fundamental equations are only useful when their assumptions match the actual problem.

11 // Technical references

ASHRAE 2025 is the primary source basis. The sheet uses mass-based equations where practical and labels common approximations as approximations.

12 // Related EngineerHub tools